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2.25x^2+2x-1=0
a = 2.25; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·2.25·(-1)
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{13}}{2*2.25}=\frac{-2-\sqrt{13}}{4.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{13}}{2*2.25}=\frac{-2+\sqrt{13}}{4.5} $
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